Optimal. Leaf size=776 \[ -\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}-\frac {77 b (b c-a d) (a+b x)^{3/4} (c+d x)^{3/4}}{15 d^3}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}+\frac {77 \sqrt {b} (b c-a d) \sqrt {(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2} \sqrt {(a d+b (c+2 d x))^2}}{10 d^{7/2} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x) \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )}-\frac {77 \sqrt [4]{b} (b c-a d)^{7/2} \sqrt [4]{(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2} \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{10 \sqrt {2} d^{15/4} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x) \sqrt {(a d+b (c+2 d x))^2}}+\frac {77 \sqrt [4]{b} (b c-a d)^{7/2} \sqrt [4]{(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2} \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{20 \sqrt {2} d^{15/4} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x) \sqrt {(a d+b (c+2 d x))^2}} \]
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Rubi [A]
time = 0.63, antiderivative size = 776, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.368, Rules used = {49, 52, 64, 637,
311, 226, 1210} \begin {gather*} \frac {77 \sqrt [4]{b} (b c-a d)^{7/2} \sqrt [4]{(a+b x) (c+d x)} \sqrt {(a d+b c+2 b d x)^2} \left (\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} F\left (2 \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{20 \sqrt {2} d^{15/4} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (a d+b c+2 b d x) \sqrt {(a d+b (c+2 d x))^2}}-\frac {77 \sqrt [4]{b} (b c-a d)^{7/2} \sqrt [4]{(a+b x) (c+d x)} \sqrt {(a d+b c+2 b d x)^2} \left (\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}+1\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}+1\right )^2}} E\left (2 \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{10 \sqrt {2} d^{15/4} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (a d+b c+2 b d x) \sqrt {(a d+b (c+2 d x))^2}}+\frac {77 \sqrt {b} (b c-a d) \sqrt {(a+b x) (c+d x)} \sqrt {(a d+b c+2 b d x)^2} \sqrt {(a d+b (c+2 d x))^2}}{10 d^{7/2} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (a d+b c+2 b d x) \left (\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}+1\right )}-\frac {77 b (a+b x)^{3/4} (c+d x)^{3/4} (b c-a d)}{15 d^3}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}} \end {gather*}
Antiderivative was successfully verified.
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Rule 49
Rule 52
Rule 64
Rule 226
Rule 311
Rule 637
Rule 1210
Rubi steps
\begin {align*} \int \frac {(a+b x)^{11/4}}{(c+d x)^{5/4}} \, dx &=-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}+\frac {(11 b) \int \frac {(a+b x)^{7/4}}{\sqrt [4]{c+d x}} \, dx}{d}\\ &=-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}-\frac {(77 b (b c-a d)) \int \frac {(a+b x)^{3/4}}{\sqrt [4]{c+d x}} \, dx}{10 d^2}\\ &=-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}-\frac {77 b (b c-a d) (a+b x)^{3/4} (c+d x)^{3/4}}{15 d^3}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}+\frac {\left (77 b (b c-a d)^2\right ) \int \frac {1}{\sqrt [4]{a+b x} \sqrt [4]{c+d x}} \, dx}{20 d^3}\\ &=-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}-\frac {77 b (b c-a d) (a+b x)^{3/4} (c+d x)^{3/4}}{15 d^3}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}+\frac {\left (77 b (b c-a d)^2 \sqrt [4]{(a+b x) (c+d x)}\right ) \int \frac {1}{\sqrt [4]{a c+(b c+a d) x+b d x^2}} \, dx}{20 d^3 \sqrt [4]{a+b x} \sqrt [4]{c+d x}}\\ &=-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}-\frac {77 b (b c-a d) (a+b x)^{3/4} (c+d x)^{3/4}}{15 d^3}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}+\frac {\left (77 b (b c-a d)^2 \sqrt [4]{(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {-4 a b c d+(b c+a d)^2+4 b d x^4}} \, dx,x,\sqrt [4]{(a+b x) (c+d x)}\right )}{5 d^3 \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x)}\\ &=-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}-\frac {77 b (b c-a d) (a+b x)^{3/4} (c+d x)^{3/4}}{15 d^3}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}+\frac {\left (77 \sqrt {b} (b c-a d)^3 \sqrt [4]{(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-4 a b c d+(b c+a d)^2+4 b d x^4}} \, dx,x,\sqrt [4]{(a+b x) (c+d x)}\right )}{10 d^{7/2} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x)}-\frac {\left (77 \sqrt {b} (b c-a d)^3 \sqrt [4]{(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2}\right ) \text {Subst}\left (\int \frac {1-\frac {2 \sqrt {b} \sqrt {d} x^2}{b c-a d}}{\sqrt {-4 a b c d+(b c+a d)^2+4 b d x^4}} \, dx,x,\sqrt [4]{(a+b x) (c+d x)}\right )}{10 d^{7/2} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x)}\\ &=-\frac {4 (a+b x)^{11/4}}{d \sqrt [4]{c+d x}}-\frac {77 b (b c-a d) (a+b x)^{3/4} (c+d x)^{3/4}}{15 d^3}+\frac {22 b (a+b x)^{7/4} (c+d x)^{3/4}}{5 d^2}+\frac {77 \sqrt {b} (b c-a d) \sqrt {(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2} \sqrt {(a d+b (c+2 d x))^2}}{10 d^{7/2} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x) \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )}-\frac {77 \sqrt [4]{b} (b c-a d)^{7/2} \sqrt [4]{(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2} \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{10 \sqrt {2} d^{15/4} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x) \sqrt {(a d+b (c+2 d x))^2}}+\frac {77 \sqrt [4]{b} (b c-a d)^{7/2} \sqrt [4]{(a+b x) (c+d x)} \sqrt {(b c+a d+2 b d x)^2} \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right ) \sqrt {\frac {(a d+b (c+2 d x))^2}{(b c-a d)^2 \left (1+\frac {2 \sqrt {b} \sqrt {d} \sqrt {(a+b x) (c+d x)}}{b c-a d}\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{d} \sqrt [4]{(a+b x) (c+d x)}}{\sqrt {b c-a d}}\right )|\frac {1}{2}\right )}{20 \sqrt {2} d^{15/4} \sqrt [4]{a+b x} \sqrt [4]{c+d x} (b c+a d+2 b d x) \sqrt {(a d+b (c+2 d x))^2}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 10.06, size = 73, normalized size = 0.09 \begin {gather*} \frac {4 (a+b x)^{15/4} \left (\frac {b (c+d x)}{b c-a d}\right )^{5/4} \, _2F_1\left (\frac {5}{4},\frac {15}{4};\frac {19}{4};\frac {d (a+b x)}{-b c+a d}\right )}{15 b (c+d x)^{5/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.07, size = 0, normalized size = 0.00 \[\int \frac {\left (b x +a \right )^{\frac {11}{4}}}{\left (d x +c \right )^{\frac {5}{4}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b x\right )^{\frac {11}{4}}}{\left (c + d x\right )^{\frac {5}{4}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a+b\,x\right )}^{11/4}}{{\left (c+d\,x\right )}^{5/4}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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